tag:blogger.com,1999:blog-7691251033406320222.post4259812479699117611..comments2024-03-26T04:19:38.862-07:00Comments on kitchen table math, the sequel: Algebra Review for Pre-Calculus (follow-up)Catherine Johnsonhttp://www.blogger.com/profile/03347093496361370174noreply@blogger.comBlogger8125tag:blogger.com,1999:blog-7691251033406320222.post-47006599046792943772011-07-30T13:11:15.269-07:002011-07-30T13:11:15.269-07:00Catherine's right, there is a disconnect betwe...Catherine's right, there is a disconnect between college level remedial math at selective colleges and what we mean when we talk about remedial math at a community college. A remedial math course at a private liberal arts college is probably at least algebra II (sometimes misleadingly called college algebra), which isn't tested on the math SAT.<br /><br />At my moderately selective school, a chunk of students interested in STEM need to start with pre-calculus, which we consider remedial. A few could really use an algebra course, but they were usually admitted as transfers, who don't need SATs at all.ChemProfnoreply@blogger.comtag:blogger.com,1999:blog-7691251033406320222.post-52202486436516074492011-07-30T12:13:35.836-07:002011-07-30T12:13:35.836-07:00I have answers keys on my computer at work - I'...I have answers keys on my computer at work - I'll try to get them up this week.Rich Beveridgehttps://www.blogger.com/profile/16100616031187198677noreply@blogger.comtag:blogger.com,1999:blog-7691251033406320222.post-35415375701426182852011-07-30T08:07:54.105-07:002011-07-30T08:07:54.105-07:00Hey Rich - any chance you could post the solutions...Hey Rich - any chance you could post the solutions to your questions? (Or email them to me?)<br /><br />Thanks!Catherine Johnsonhttps://www.blogger.com/profile/03347093496361370174noreply@blogger.comtag:blogger.com,1999:blog-7691251033406320222.post-27962732565765592692011-07-30T08:04:12.090-07:002011-07-30T08:04:12.090-07:00I have a disconnect between the SAT scores necessa...<i>I have a disconnect between the SAT scores necessary to get admitted to these schools and the large percentage of kids who apparently cannot do college level math.</i><br /><br />Hi Dee - Sorry you're having trouble posting - !<br /><br />Do we know how high the remediation rate is at selective colleges?<br /><br />Assuming high-math-SAT students admitted to selective colleges are taking remedial courses, the answer would be that SAT-I tests content from algebra 1, geometry (not including proofs), and just a bit of what I think of as algebra 2.Catherine Johnsonhttps://www.blogger.com/profile/03347093496361370174noreply@blogger.comtag:blogger.com,1999:blog-7691251033406320222.post-29962229849815986992011-07-29T09:26:41.251-07:002011-07-29T09:26:41.251-07:00If you assume P(x)/(x^2-4x+3)=Q(x)+(65x-68)/(x^2-4...If you assume P(x)/(x^2-4x+3)=Q(x)+(65x-68)/(x^2-4x+3)<br /><br />then multiply through by x-3, so<br /><br />P(x)/(x-1)=Q(x)(x-3)+<br />(65x-68)/(x-1)<br /><br />then the remainder when P(x) is divided by (x-1) is also 65x-68, so you can say that P(1)=65(1)-68=-3, or if you do the long division for (65x-68)/(x-1) you come out with a remainder of -3.<br /><br />Do the same thing to condition (B) so that -3=-5(1)+a and a=2.<br /><br />I don't know if there's an easier way to go about this or not...Rich Beveridgehttps://www.blogger.com/profile/16100616031187198677noreply@blogger.comtag:blogger.com,1999:blog-7691251033406320222.post-23355509885944236592011-07-29T06:29:56.823-07:002011-07-29T06:29:56.823-07:00Hi Catherine
This should probably go on the main p...Hi Catherine<br />This should probably go on the main page but I still havent figured out how to do that...<br /><br />In a recent conversation I was speaking about the high percentage of students entering universities that have to take remedial math. I think this point was mentioned in Waiting for Superman as well...<br /><br />I have a disconnect between the SAT scores necessary to get admitted to these schools and the large percentage of kids who apparently cannot do college level math. How can kids score high on the math portion of the SAT yet still not be able to do math?<br /><br />Am I missing something here? I would love any insights that the KTM community may provide..<br /><br />Dee HodsonDee Hodsonhttps://www.blogger.com/profile/01188093717962091917noreply@blogger.comtag:blogger.com,1999:blog-7691251033406320222.post-85437473101243235542011-07-28T20:38:02.241-07:002011-07-28T20:38:02.241-07:00I solved this by assuming that P(x) is quadratic, ...I solved this by assuming that P(x) is quadratic, but I realize that's not necessarily a valid assumption, and I don't remember enough to know whether you could get a different answer from a higher order polynomial.GoogleMasternoreply@blogger.comtag:blogger.com,1999:blog-7691251033406320222.post-70735154205091149512011-07-28T15:34:03.650-07:002011-07-28T15:34:03.650-07:00In using the Remainder Theorem to solve this you a...In using the Remainder Theorem to solve this you actually have to split the original divisors into their binomial factors. Notice that the two divisors share a factor.Rich Beveridgehttps://www.blogger.com/profile/16100616031187198677noreply@blogger.com